You probably know the use of math expressions in Neobook's SetVar:
Code: Select all
SetVar "[z]" "10"
SetVar "[z]" "[z]+1"
Best regards,
Reinier
Code: Select all
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.Examples of math expressions in Neobook's SetVar and
.control commands If, IfEx, While, WhileEx and Loop
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SetVar "[x]" "3"
SetVar "[y]" "2"
SetVar "[z]" "1"
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While "[z]" "<" "3"
AlertBox "Result 1" "Value of variable z: [z]"
SetVar "[z]" "[z]+1"
EndWhile
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If "[x]+[y]" ">" "[z]"
AlertBox "Result 2" "[x]+[y] > [z] is TRUE"
Else
AlertBox "Result 2" "[x]+[y] > [z] is FALSE"
EndIf
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IfEx "[x]+[y] > [z] AND [x]-[y] = [z]"
AlertBox "Result 3" "[x]+[y] > [z] AND [x]-[y] = [z] is TRUE"
Else
AlertBox "Result 3" "[x]+[y] > [z] AND [x]-[y] = [z] is FALSE"
EndIf
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WhileEx "[x]^2 > 0 AND [x]*[y] > 0"
AlertBox "Result 4" "Value of variable x and y: [x] and [y]"
SetVar "[x]" "[x]-1"
SetVar "[y]" "[y]-1"
EndWhile
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.initialize [y] again because of the last example
SetVar "[y]" "2"
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If "Sqrt([y])" "<" "[z]"
AlertBox "Result 5" "Sqrt([y]) < [z] is TRUE"
Else
AlertBox "Result 5" "Sqrt([y]) < [z] is FALSE"
EndIf
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.solving an equation for a > 0
Loop "1" "Sqr([y]+[z])" "[a]"
If "[a]*[a]-3*[a]-3" "=" "[a]-3"
AlertBox "Result 6" "a*a-3a-3 = a-3 is TRUE for value [a]"
ExitLoop
EndIf
EndLoop
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. Try it yourself and use Neobook's math operators and functions:
. + - * / ^
. Abs
. Sin Cos Atan,
. Sqr Sqrt Round Trunc